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8x^2+225x-1800=0
a = 8; b = 225; c = -1800;
Δ = b2-4ac
Δ = 2252-4·8·(-1800)
Δ = 108225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108225}=\sqrt{225*481}=\sqrt{225}*\sqrt{481}=15\sqrt{481}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(225)-15\sqrt{481}}{2*8}=\frac{-225-15\sqrt{481}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(225)+15\sqrt{481}}{2*8}=\frac{-225+15\sqrt{481}}{16} $
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